Showing 2 of 4 total issues
remote? has a Cognitive Complexity of 7 (exceeds 5 allowed). Consider refactoring. Open
def remote?(url) return false unless url parsed = URI.parse(url) return false if parsed.scheme == 'sqlite3:'
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Cognitive Complexity is a measure of how difficult a unit of code is to intuitively understand. Unlike Cyclomatic Complexity, which determines how difficult your code will be to test, Cognitive Complexity tells you how difficult your code will be to read and comprehend.
A method's cognitive complexity is based on a few simple rules:
- Code is not considered more complex when it uses shorthand that the language provides for collapsing multiple statements into one
- Code is considered more complex for each "break in the linear flow of the code"
- Code is considered more complex when "flow breaking structures are nested"
Avoid too many
return statements within this method. Open
return false if host.end_with? '.local'