Showing 5 of 9 total issues
Method valid_resource?
has a Cognitive Complexity of 14 (exceeds 5 allowed). Consider refactoring. Open
Open
def valid_resource?(resource)
return false if resource.nil?
# A KeyboardButton can be a simple String.
# So if it is string like, return true because it
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Cognitive Complexity
Cognitive Complexity is a measure of how difficult a unit of code is to intuitively understand. Unlike Cyclomatic Complexity, which determines how difficult your code will be to test, Cognitive Complexity tells you how difficult your code will be to read and comprehend.
A method's cognitive complexity is based on a few simple rules:
- Code is not considered more complex when it uses shorthand that the language provides for collapsing multiple statements into one
- Code is considered more complex for each "break in the linear flow of the code"
- Code is considered more complex when "flow breaking structures are nested"
Further reading
Method valid_resource?
has a Cognitive Complexity of 14 (exceeds 5 allowed). Consider refactoring. Open
Open
def valid_resource?(resource)
return false if resource.nil? || !resource.respond_to?('[]')
required_fields.each do |f|
return false if resource[f].nil?
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Cognitive Complexity
Cognitive Complexity is a measure of how difficult a unit of code is to intuitively understand. Unlike Cyclomatic Complexity, which determines how difficult your code will be to test, Cognitive Complexity tells you how difficult your code will be to read and comprehend.
A method's cognitive complexity is based on a few simple rules:
- Code is not considered more complex when it uses shorthand that the language provides for collapsing multiple statements into one
- Code is considered more complex for each "break in the linear flow of the code"
- Code is considered more complex when "flow breaking structures are nested"
Further reading
Avoid too many return
statements within this method. Open
Open
return false unless a[:type].valid_resource?(el)
Avoid too many return
statements within this method. Open
Open
return false unless arr.respond_to?('each')
Avoid too many return
statements within this method. Open
Open
return false unless a[:type].valid_resource?(el)