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Expected 2 blank lines, found 1 Open
@simplifier
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Separate top-level function and class definitions with two blank lines.
Method definitions inside a class are separated by a single blank
line.
Extra blank lines may be used (sparingly) to separate groups of
related functions. Blank lines may be omitted between a bunch of
related one-liners (e.g. a set of dummy implementations).
Use blank lines in functions, sparingly, to indicate logical
sections.
Okay: def a():\n pass\n\n\ndef b():\n pass
Okay: def a():\n pass\n\n\nasync def b():\n pass
Okay: def a():\n pass\n\n\n# Foo\n# Bar\n\ndef b():\n pass
Okay: default = 1\nfoo = 1
Okay: classify = 1\nfoo = 1
E301: class Foo:\n b = 0\n def bar():\n pass
E302: def a():\n pass\n\ndef b(n):\n pass
E302: def a():\n pass\n\nasync def b(n):\n pass
E303: def a():\n pass\n\n\n\ndef b(n):\n pass
E303: def a():\n\n\n\n pass
E304: @decorator\n\ndef a():\n pass
E305: def a():\n pass\na()
E306: def a():\n def b():\n pass\n def c():\n pass
Continuation line with same indent as next logical line Open
expr.op1.op1 == expr.op2.op1 and expr.op1.op2 == expr.op2.op2:
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Continuation lines indentation.
Continuation lines should align wrapped elements either vertically
using Python's implicit line joining inside parentheses, brackets
and braces, or using a hanging indent.
When using a hanging indent these considerations should be applied:
- there should be no arguments on the first line, and
- further indentation should be used to clearly distinguish itself
as a continuation line.
Okay: a = (\n)
E123: a = (\n )
Okay: a = (\n 42)
E121: a = (\n 42)
E122: a = (\n42)
E123: a = (\n 42\n )
E124: a = (24,\n 42\n)
E125: if (\n b):\n pass
E126: a = (\n 42)
E127: a = (24,\n 42)
E128: a = (24,\n 42)
E129: if (a or\n b):\n pass
E131: a = (\n 42\n 24)
Multiple spaces after operator Open
cls = {leq_t: lower_t, aeq_t: above_t, above_t: above_t, lower_t: lower_t}[type(expr.op1)]
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Avoid extraneous whitespace around an operator.
Okay: a = 12 + 3
E221: a = 4 + 5
E222: a = 4 + 5
E223: a = 4\t+ 5
E224: a = 4 +\t5
Indentation is not a multiple of 4 Open
break
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Use indent_size (PEP8 says 4) spaces per indentation level.
For really old code that you don't want to mess up, you can continue
to use 8-space tabs.
Okay: a = 1
Okay: if a == 0:\n a = 1
E111: a = 1
E114: # a = 1
Okay: for item in items:\n pass
E112: for item in items:\npass
E115: for item in items:\n# Hi\n pass
Okay: a = 1\nb = 2
E113: a = 1\n b = 2
E116: a = 1\n # b = 2
Indentation is not a multiple of 4 Open
""" transform the and (&) operator into a simpler form in the special case
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Use indent_size (PEP8 says 4) spaces per indentation level.
For really old code that you don't want to mess up, you can continue
to use 8-space tabs.
Okay: a = 1
Okay: if a == 0:\n a = 1
E111: a = 1
E114: # a = 1
Okay: for item in items:\n pass
E112: for item in items:\npass
E115: for item in items:\n# Hi\n pass
Okay: a = 1\nb = 2
E113: a = 1\n b = 2
E116: a = 1\n # b = 2
Line too long (94 > 79 characters) Open
- Provide disassembler output: instruction size, mnemonic, number of operands, operands types.
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Limit all lines to a maximum of 79 characters.
There are still many devices around that are limited to 80 character
lines; plus, limiting windows to 80 characters makes it possible to
have several windows side-by-side. The default wrapping on such
devices looks ugly. Therefore, please limit all lines to a maximum
of 79 characters. For flowing long blocks of text (docstrings or
comments), limiting the length to 72 characters is recommended.
Reports error E501.
Indentation is not a multiple of 4 Open
if type(expr) == and_t and expr.op1 == expr.op2:
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Use indent_size (PEP8 says 4) spaces per indentation level.
For really old code that you don't want to mess up, you can continue
to use 8-space tabs.
Okay: a = 1
Okay: if a == 0:\n a = 1
E111: a = 1
E114: # a = 1
Okay: for item in items:\n pass
E112: for item in items:\npass
E115: for item in items:\n# Hi\n pass
Okay: a = 1\nb = 2
E113: a = 1\n b = 2
E116: a = 1\n # b = 2
Indentation is not a multiple of 4 Open
import capstone # try importing capstone.
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Use indent_size (PEP8 says 4) spaces per indentation level.
For really old code that you don't want to mess up, you can continue
to use 8-space tabs.
Okay: a = 1
Okay: if a == 0:\n a = 1
E111: a = 1
E114: # a = 1
Okay: for item in items:\n pass
E112: for item in items:\npass
E115: for item in items:\n# Hi\n pass
Okay: a = 1\nb = 2
E113: a = 1\n b = 2
E116: a = 1\n # b = 2
Indentation is not a multiple of 4 Open
while True:
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Use indent_size (PEP8 says 4) spaces per indentation level.
For really old code that you don't want to mess up, you can continue
to use 8-space tabs.
Okay: a = 1
Okay: if a == 0:\n a = 1
E111: a = 1
E114: # a = 1
Okay: for item in items:\n pass
E112: for item in items:\npass
E115: for item in items:\n# Hi\n pass
Okay: a = 1\nb = 2
E113: a = 1\n b = 2
E116: a = 1\n # b = 2
Indentation is not a multiple of 4 Open
if type(expr) == b_not_t and type(expr.op) == above_t:
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Use indent_size (PEP8 says 4) spaces per indentation level.
For really old code that you don't want to mess up, you can continue
to use 8-space tabs.
Okay: a = 1
Okay: if a == 0:\n a = 1
E111: a = 1
E114: # a = 1
Okay: for item in items:\n pass
E112: for item in items:\npass
E115: for item in items:\n# Hi\n pass
Okay: a = 1\nb = 2
E113: a = 1\n b = 2
E116: a = 1\n # b = 2
Missing whitespace after ',' Open
brush = QtGui.QBrush(QtGui.QColor(0xff,0xff,0x00,200))
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Each comma, semicolon or colon should be followed by whitespace.
Okay: [a, b]
Okay: (3,)
Okay: a[1:4]
Okay: a[:4]
Okay: a[1:]
Okay: a[1:4:2]
E231: ['a','b']
E231: foo(bar,baz)
E231: [{'a':'b'}]
Indentation is not a multiple of 4 Open
available_disassemblers['ida'] = ida.dis
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Use indent_size (PEP8 says 4) spaces per indentation level.
For really old code that you don't want to mess up, you can continue
to use 8-space tabs.
Okay: a = 1
Okay: if a == 0:\n a = 1
E111: a = 1
E114: # a = 1
Okay: for item in items:\n pass
E112: for item in items:\npass
E115: for item in items:\n# Hi\n pass
Okay: a = 1\nb = 2
E113: a = 1\n b = 2
E116: a = 1\n # b = 2
Indentation is not a multiple of 4 Open
print 'Using Capstone backend.'
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Use indent_size (PEP8 says 4) spaces per indentation level.
For really old code that you don't want to mess up, you can continue
to use 8-space tabs.
Okay: a = 1
Okay: if a == 0:\n a = 1
E111: a = 1
E114: # a = 1
Okay: for item in items:\n pass
E112: for item in items:\npass
E115: for item in items:\n# Hi\n pass
Okay: a = 1\nb = 2
E113: a = 1\n b = 2
E116: a = 1\n # b = 2
Indentation is not a multiple of 4 (comment) Open
# a > b || a == b becomes a >= b
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Use indent_size (PEP8 says 4) spaces per indentation level.
For really old code that you don't want to mess up, you can continue
to use 8-space tabs.
Okay: a = 1
Okay: if a == 0:\n a = 1
E111: a = 1
E114: # a = 1
Okay: for item in items:\n pass
E112: for item in items:\npass
E115: for item in items:\n# Hi\n pass
Okay: a = 1\nb = 2
E113: a = 1\n b = 2
E116: a = 1\n # b = 2
Indentation is not a multiple of 4 Open
traceback.print_exc()
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Use indent_size (PEP8 says 4) spaces per indentation level.
For really old code that you don't want to mess up, you can continue
to use 8-space tabs.
Okay: a = 1
Okay: if a == 0:\n a = 1
E111: a = 1
E114: # a = 1
Okay: for item in items:\n pass
E112: for item in items:\npass
E115: for item in items:\n# Hi\n pass
Okay: a = 1\nb = 2
E113: a = 1\n b = 2
E116: a = 1\n # b = 2
Indentation is not a multiple of 4 (comment) Open
# a >= b || a == b becomes a >= b
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- Exclude checks
Use indent_size (PEP8 says 4) spaces per indentation level.
For really old code that you don't want to mess up, you can continue
to use 8-space tabs.
Okay: a = 1
Okay: if a == 0:\n a = 1
E111: a = 1
E114: # a = 1
Okay: for item in items:\n pass
E112: for item in items:\npass
E115: for item in items:\n# Hi\n pass
Okay: a = 1\nb = 2
E113: a = 1\n b = 2
E116: a = 1\n # b = 2
Indentation is not a multiple of 4 Open
""" combine expressions until they cannot be combined any more.
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- Exclude checks
Use indent_size (PEP8 says 4) spaces per indentation level.
For really old code that you don't want to mess up, you can continue
to use 8-space tabs.
Okay: a = 1
Okay: if a == 0:\n a = 1
E111: a = 1
E114: # a = 1
Okay: for item in items:\n pass
E112: for item in items:\npass
E115: for item in items:\n# Hi\n pass
Okay: a = 1\nb = 2
E113: a = 1\n b = 2
E116: a = 1\n # b = 2
Indentation is not a multiple of 4 Open
from .ida.ui import *
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Use indent_size (PEP8 says 4) spaces per indentation level.
For really old code that you don't want to mess up, you can continue
to use 8-space tabs.
Okay: a = 1
Okay: if a == 0:\n a = 1
E111: a = 1
E114: # a = 1
Okay: for item in items:\n pass
E112: for item in items:\npass
E115: for item in items:\n# Hi\n pass
Okay: a = 1\nb = 2
E113: a = 1\n b = 2
E116: a = 1\n # b = 2
Indentation is not a multiple of 4 Open
from PySide import QtCore, QtGui
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- Exclude checks
Use indent_size (PEP8 says 4) spaces per indentation level.
For really old code that you don't want to mess up, you can continue
to use 8-space tabs.
Okay: a = 1
Okay: if a == 0:\n a = 1
E111: a = 1
E114: # a = 1
Okay: for item in items:\n pass
E112: for item in items:\npass
E115: for item in items:\n# Hi\n pass
Okay: a = 1\nb = 2
E113: a = 1\n b = 2
E116: a = 1\n # b = 2
Indentation is not a multiple of 4 Open
def __init__(self, parent=None):
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Use indent_size (PEP8 says 4) spaces per indentation level.
For really old code that you don't want to mess up, you can continue
to use 8-space tabs.
Okay: a = 1
Okay: if a == 0:\n a = 1
E111: a = 1
E114: # a = 1
Okay: for item in items:\n pass
E112: for item in items:\npass
E115: for item in items:\n# Hi\n pass
Okay: a = 1\nb = 2
E113: a = 1\n b = 2
E116: a = 1\n # b = 2