Showing 2,968 of 2,968 total issues
Indentation is not a multiple of 4 Open
stmt = self.make_statement(item, expr)
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- Exclude checks
Use indent_size (PEP8 says 4) spaces per indentation level.
For really old code that you don't want to mess up, you can continue
to use 8-space tabs.
Okay: a = 1
Okay: if a == 0:\n a = 1
E111: a = 1
E114: # a = 1
Okay: for item in items:\n pass
E112: for item in items:\npass
E115: for item in items:\n# Hi\n pass
Okay: a = 1\nb = 2
E113: a = 1\n b = 2
E116: a = 1\n # b = 2
Indentation is not a multiple of 4 Open
node.statements.append(stmt)
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- Exclude checks
Use indent_size (PEP8 says 4) spaces per indentation level.
For really old code that you don't want to mess up, you can continue
to use 8-space tabs.
Okay: a = 1
Okay: if a == 0:\n a = 1
E111: a = 1
E114: # a = 1
Okay: for item in items:\n pass
E112: for item in items:\npass
E115: for item in items:\n# Hi\n pass
Okay: a = 1\nb = 2
E113: a = 1\n b = 2
E116: a = 1\n # b = 2
Indentation is not a multiple of 4 Open
for expr in list(stmt.expressions):
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- Exclude checks
Use indent_size (PEP8 says 4) spaces per indentation level.
For really old code that you don't want to mess up, you can continue
to use 8-space tabs.
Okay: a = 1
Okay: if a == 0:\n a = 1
E111: a = 1
E114: # a = 1
Okay: for item in items:\n pass
E112: for item in items:\npass
E115: for item in items:\n# Hi\n pass
Okay: a = 1\nb = 2
E113: a = 1\n b = 2
E116: a = 1\n # b = 2
Indentation is not a multiple of 4 Open
yield op
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- Exclude checks
Use indent_size (PEP8 says 4) spaces per indentation level.
For really old code that you don't want to mess up, you can continue
to use 8-space tabs.
Okay: a = 1
Okay: if a == 0:\n a = 1
E111: a = 1
E114: # a = 1
Okay: for item in items:\n pass
E112: for item in items:\npass
E115: for item in items:\n# Hi\n pass
Okay: a = 1\nb = 2
E113: a = 1\n b = 2
E116: a = 1\n # b = 2
Indentation is not a multiple of 4 Open
print 'Failed to decompile: %s' % repr(e)
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- Exclude checks
Use indent_size (PEP8 says 4) spaces per indentation level.
For really old code that you don't want to mess up, you can continue
to use 8-space tabs.
Okay: a = 1
Okay: if a == 0:\n a = 1
E111: a = 1
E114: # a = 1
Okay: for item in items:\n pass
E112: for item in items:\npass
E115: for item in items:\n# Hi\n pass
Okay: a = 1\nb = 2
E113: a = 1\n b = 2
E116: a = 1\n # b = 2
Indentation is not a multiple of 4 Open
def __init__(self, function):
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- Exclude checks
Use indent_size (PEP8 says 4) spaces per indentation level.
For really old code that you don't want to mess up, you can continue
to use 8-space tabs.
Okay: a = 1
Okay: if a == 0:\n a = 1
E111: a = 1
E114: # a = 1
Okay: for item in items:\n pass
E112: for item in items:\npass
E115: for item in items:\n# Hi\n pass
Okay: a = 1\nb = 2
E113: a = 1\n b = 2
E116: a = 1\n # b = 2
Expected 2 blank lines, found 1 Open
class phi_propagator_t(propagator_t):
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Separate top-level function and class definitions with two blank lines.
Method definitions inside a class are separated by a single blank
line.
Extra blank lines may be used (sparingly) to separate groups of
related functions. Blank lines may be omitted between a bunch of
related one-liners (e.g. a set of dummy implementations).
Use blank lines in functions, sparingly, to indicate logical
sections.
Okay: def a():\n pass\n\n\ndef b():\n pass
Okay: def a():\n pass\n\n\nasync def b():\n pass
Okay: def a():\n pass\n\n\n# Foo\n# Bar\n\ndef b():\n pass
Okay: default = 1\nfoo = 1
Okay: classify = 1\nfoo = 1
E301: class Foo:\n b = 0\n def bar():\n pass
E302: def a():\n pass\n\ndef b(n):\n pass
E302: def a():\n pass\n\nasync def b(n):\n pass
E303: def a():\n pass\n\n\n\ndef b(n):\n pass
E303: def a():\n\n\n\n pass
E304: @decorator\n\ndef a():\n pass
E305: def a():\n pass\na()
E306: def a():\n def b():\n pass\n def c():\n pass
Continuation line with same indent as next logical line Open
self.is_stack_location(value):
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Continuation lines indentation.
Continuation lines should align wrapped elements either vertically
using Python's implicit line joining inside parentheses, brackets
and braces, or using a hanging indent.
When using a hanging indent these considerations should be applied:
- there should be no arguments on the first line, and
- further indentation should be used to clearly distinguish itself
as a continuation line.
Okay: a = (\n)
E123: a = (\n )
Okay: a = (\n 42)
E121: a = (\n 42)
E122: a = (\n42)
E123: a = (\n 42\n )
E124: a = (24,\n 42\n)
E125: if (\n b):\n pass
E126: a = (\n 42)
E127: a = (24,\n 42)
E128: a = (24,\n 42)
E129: if (a or\n b):\n pass
E131: a = (\n 42\n 24)
Indentation is not a multiple of 4 Open
return False
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- Exclude checks
Use indent_size (PEP8 says 4) spaces per indentation level.
For really old code that you don't want to mess up, you can continue
to use 8-space tabs.
Okay: a = 1
Okay: if a == 0:\n a = 1
E111: a = 1
E114: # a = 1
Okay: for item in items:\n pass
E112: for item in items:\npass
E115: for item in items:\n# Hi\n pass
Okay: a = 1\nb = 2
E113: a = 1\n b = 2
E116: a = 1\n # b = 2
Indentation is not a multiple of 4 Open
return False
- Read upRead up
- Exclude checks
Use indent_size (PEP8 says 4) spaces per indentation level.
For really old code that you don't want to mess up, you can continue
to use 8-space tabs.
Okay: a = 1
Okay: if a == 0:\n a = 1
E111: a = 1
E114: # a = 1
Okay: for item in items:\n pass
E112: for item in items:\npass
E115: for item in items:\n# Hi\n pass
Okay: a = 1\nb = 2
E113: a = 1\n b = 2
E116: a = 1\n # b = 2
Indentation is not a multiple of 4 Open
if expr.definition in self.function.uninitialized and len(expr.definition.uses) > 1:
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- Exclude checks
Use indent_size (PEP8 says 4) spaces per indentation level.
For really old code that you don't want to mess up, you can continue
to use 8-space tabs.
Okay: a = 1
Okay: if a == 0:\n a = 1
E111: a = 1
E114: # a = 1
Okay: for item in items:\n pass
E112: for item in items:\npass
E115: for item in items:\n# Hi\n pass
Okay: a = 1\nb = 2
E113: a = 1\n b = 2
E116: a = 1\n # b = 2
Indentation is not a multiple of 4 Open
return False
- Read upRead up
- Exclude checks
Use indent_size (PEP8 says 4) spaces per indentation level.
For really old code that you don't want to mess up, you can continue
to use 8-space tabs.
Okay: a = 1
Okay: if a == 0:\n a = 1
E111: a = 1
E114: # a = 1
Okay: for item in items:\n pass
E112: for item in items:\npass
E115: for item in items:\n# Hi\n pass
Okay: a = 1\nb = 2
E113: a = 1\n b = 2
E116: a = 1\n # b = 2
Multiple spaces after keyword Open
if isinstance(expr, assignable_t) and expr.definition:
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Avoid extraneous whitespace around keywords.
Okay: True and False
E271: True and False
E272: True and False
E273: True and\tFalse
E274: True\tand False
Indentation is not a multiple of 4 (comment) Open
# 'esp - 4'
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Use indent_size (PEP8 says 4) spaces per indentation level.
For really old code that you don't want to mess up, you can continue
to use 8-space tabs.
Okay: a = 1
Okay: if a == 0:\n a = 1
E111: a = 1
E114: # a = 1
Okay: for item in items:\n pass
E112: for item in items:\npass
E115: for item in items:\n# Hi\n pass
Okay: a = 1\nb = 2
E113: a = 1\n b = 2
E116: a = 1\n # b = 2
Indentation is not a multiple of 4 Open
""" the context holds live locations at any given point in time.
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- Exclude checks
Use indent_size (PEP8 says 4) spaces per indentation level.
For really old code that you don't want to mess up, you can continue
to use 8-space tabs.
Okay: a = 1
Okay: if a == 0:\n a = 1
E111: a = 1
E114: # a = 1
Okay: for item in items:\n pass
E112: for item in items:\npass
E115: for item in items:\n# Hi\n pass
Okay: a = 1\nb = 2
E113: a = 1\n b = 2
E116: a = 1\n # b = 2
Indentation is not a multiple of 4 Open
def __init__(self, function, selector):
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- Exclude checks
Use indent_size (PEP8 says 4) spaces per indentation level.
For really old code that you don't want to mess up, you can continue
to use 8-space tabs.
Okay: a = 1
Okay: if a == 0:\n a = 1
E111: a = 1
E114: # a = 1
Okay: for item in items:\n pass
E112: for item in items:\npass
E115: for item in items:\n# Hi\n pass
Okay: a = 1\nb = 2
E113: a = 1\n b = 2
E116: a = 1\n # b = 2
Indentation is not a multiple of 4 Open
target = self.function.blocks[stmt.expr.value]
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- Exclude checks
Use indent_size (PEP8 says 4) spaces per indentation level.
For really old code that you don't want to mess up, you can continue
to use 8-space tabs.
Okay: a = 1
Okay: if a == 0:\n a = 1
E111: a = 1
E114: # a = 1
Okay: for item in items:\n pass
E112: for item in items:\npass
E115: for item in items:\n# Hi\n pass
Okay: a = 1\nb = 2
E113: a = 1\n b = 2
E116: a = 1\n # b = 2
Indentation is not a multiple of 4 Open
""" phase 1: collect live assignments at the end of each block """
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- Exclude checks
Use indent_size (PEP8 says 4) spaces per indentation level.
For really old code that you don't want to mess up, you can continue
to use 8-space tabs.
Okay: a = 1
Okay: if a == 0:\n a = 1
E111: a = 1
E114: # a = 1
Okay: for item in items:\n pass
E112: for item in items:\npass
E115: for item in items:\n# Hi\n pass
Okay: a = 1\nb = 2
E113: a = 1\n b = 2
E116: a = 1\n # b = 2
Line too long (80 > 79 characters) Open
external_defs = self.fetch_recursive_definitions_for_contexts(contexts, use)
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Limit all lines to a maximum of 79 characters.
There are still many devices around that are limited to 80 character
lines; plus, limiting windows to 80 characters makes it possible to
have several windows side-by-side. The default wrapping on such
devices looks ugly. Therefore, please limit all lines to a maximum
of 79 characters. For flowing long blocks of text (docstrings or
comments), limiting the length to 72 characters is recommended.
Reports error E501.
Indentation is not a multiple of 4 Open
for use in self.uses(expr):
- Read upRead up
- Exclude checks
Use indent_size (PEP8 says 4) spaces per indentation level.
For really old code that you don't want to mess up, you can continue
to use 8-space tabs.
Okay: a = 1
Okay: if a == 0:\n a = 1
E111: a = 1
E114: # a = 1
Okay: for item in items:\n pass
E112: for item in items:\npass
E115: for item in items:\n# Hi\n pass
Okay: a = 1\nb = 2
E113: a = 1\n b = 2
E116: a = 1\n # b = 2