Showing 2,968 of 2,968 total issues
Indentation is not a multiple of 4 Open
op1 = self.get_operand_expression(ea, 0)
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- Exclude checks
Use indent_size (PEP8 says 4) spaces per indentation level.
For really old code that you don't want to mess up, you can continue
to use 8-space tabs.
Okay: a = 1
Okay: if a == 0:\n a = 1
E111: a = 1
E114: # a = 1
Okay: for item in items:\n pass
E112: for item in items:\npass
E115: for item in items:\n# Hi\n pass
Okay: a = 1\nb = 2
E113: a = 1\n b = 2
E116: a = 1\n # b = 2
Indentation is not a multiple of 4 Open
self.remove_goto(ctn, block)
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- Exclude checks
Use indent_size (PEP8 says 4) spaces per indentation level.
For really old code that you don't want to mess up, you can continue
to use 8-space tabs.
Okay: a = 1
Okay: if a == 0:\n a = 1
E111: a = 1
E114: # a = 1
Okay: for item in items:\n pass
E112: for item in items:\npass
E115: for item in items:\n# Hi\n pass
Okay: a = 1\nb = 2
E113: a = 1\n b = 2
E116: a = 1\n # b = 2
Indentation is not a multiple of 4 Open
return True
- Read upRead up
- Exclude checks
Use indent_size (PEP8 says 4) spaces per indentation level.
For really old code that you don't want to mess up, you can continue
to use 8-space tabs.
Okay: a = 1
Okay: if a == 0:\n a = 1
E111: a = 1
E114: # a = 1
Okay: for item in items:\n pass
E112: for item in items:\npass
E115: for item in items:\n# Hi\n pass
Okay: a = 1\nb = 2
E113: a = 1\n b = 2
E116: a = 1\n # b = 2
Indentation is not a multiple of 4 Open
elif mnem in ('setb', 'setc', 'setnae'):
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- Exclude checks
Use indent_size (PEP8 says 4) spaces per indentation level.
For really old code that you don't want to mess up, you can continue
to use 8-space tabs.
Okay: a = 1
Okay: if a == 0:\n a = 1
E111: a = 1
E114: # a = 1
Okay: for item in items:\n pass
E112: for item in items:\npass
E115: for item in items:\n# Hi\n pass
Okay: a = 1\nb = 2
E113: a = 1\n b = 2
E116: a = 1\n # b = 2
Indentation is not a multiple of 4 Open
if left_reach and right_reach:
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- Exclude checks
Use indent_size (PEP8 says 4) spaces per indentation level.
For really old code that you don't want to mess up, you can continue
to use 8-space tabs.
Okay: a = 1
Okay: if a == 0:\n a = 1
E111: a = 1
E114: # a = 1
Okay: for item in items:\n pass
E112: for item in items:\npass
E115: for item in items:\n# Hi\n pass
Okay: a = 1\nb = 2
E113: a = 1\n b = 2
E116: a = 1\n # b = 2
Indentation is not a multiple of 4 Open
ctn = container_t(block, [break_t(stmt.ea)])
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- Exclude checks
Use indent_size (PEP8 says 4) spaces per indentation level.
For really old code that you don't want to mess up, you can continue
to use 8-space tabs.
Okay: a = 1
Okay: if a == 0:\n a = 1
E111: a = 1
E114: # a = 1
Okay: for item in items:\n pass
E112: for item in items:\npass
E115: for item in items:\n# Hi\n pass
Okay: a = 1\nb = 2
E113: a = 1\n b = 2
E116: a = 1\n # b = 2
Indentation is not a multiple of 4 Open
elif mnem in ('setp', 'setpe'):
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- Exclude checks
Use indent_size (PEP8 says 4) spaces per indentation level.
For really old code that you don't want to mess up, you can continue
to use 8-space tabs.
Okay: a = 1
Okay: if a == 0:\n a = 1
E111: a = 1
E114: # a = 1
Okay: for item in items:\n pass
E112: for item in items:\npass
E115: for item in items:\n# Hi\n pass
Okay: a = 1\nb = 2
E113: a = 1\n b = 2
E116: a = 1\n # b = 2
Indentation is not a multiple of 4 Open
for _stmt in stmt.statements:
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- Exclude checks
Use indent_size (PEP8 says 4) spaces per indentation level.
For really old code that you don't want to mess up, you can continue
to use 8-space tabs.
Okay: a = 1
Okay: if a == 0:\n a = 1
E111: a = 1
E114: # a = 1
Okay: for item in items:\n pass
E112: for item in items:\npass
E115: for item in items:\n# Hi\n pass
Okay: a = 1\nb = 2
E113: a = 1\n b = 2
E116: a = 1\n # b = 2
Indentation is not a multiple of 4 Open
expr = assign_t(op1, cond)
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- Exclude checks
Use indent_size (PEP8 says 4) spaces per indentation level.
For really old code that you don't want to mess up, you can continue
to use 8-space tabs.
Okay: a = 1
Okay: if a == 0:\n a = 1
E111: a = 1
E114: # a = 1
Okay: for item in items:\n pass
E112: for item in items:\npass
E115: for item in items:\n# Hi\n pass
Okay: a = 1\nb = 2
E113: a = 1\n b = 2
E116: a = 1\n # b = 2
Indentation is not a multiple of 4 Open
def build_container(self, container, blocks, prioritizer=None, exclude=[]):
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- Exclude checks
Use indent_size (PEP8 says 4) spaces per indentation level.
For really old code that you don't want to mess up, you can continue
to use 8-space tabs.
Okay: a = 1
Okay: if a == 0:\n a = 1
E111: a = 1
E114: # a = 1
Okay: for item in items:\n pass
E112: for item in items:\npass
E115: for item in items:\n# Hi\n pass
Okay: a = 1\nb = 2
E113: a = 1\n b = 2
E116: a = 1\n # b = 2
Indentation is not a multiple of 4 Open
if stmt.false.value in self.function.blocks:
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- Exclude checks
Use indent_size (PEP8 says 4) spaces per indentation level.
For really old code that you don't want to mess up, you can continue
to use 8-space tabs.
Okay: a = 1
Okay: if a == 0:\n a = 1
E111: a = 1
E114: # a = 1
Okay: for item in items:\n pass
E112: for item in items:\npass
E115: for item in items:\n# Hi\n pass
Okay: a = 1\nb = 2
E113: a = 1\n b = 2
E116: a = 1\n # b = 2
Indentation is not a multiple of 4 (comment) Open
# we do not distinguish between signed and unsigned comparision here.
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- Exclude checks
Use indent_size (PEP8 says 4) spaces per indentation level.
For really old code that you don't want to mess up, you can continue
to use 8-space tabs.
Okay: a = 1
Okay: if a == 0:\n a = 1
E111: a = 1
E114: # a = 1
Okay: for item in items:\n pass
E112: for item in items:\npass
E115: for item in items:\n# Hi\n pass
Okay: a = 1\nb = 2
E113: a = 1\n b = 2
E116: a = 1\n # b = 2
Indentation is not a multiple of 4 Open
simplify_expressions.run(_if.expr, deep=True)
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- Exclude checks
Use indent_size (PEP8 says 4) spaces per indentation level.
For really old code that you don't want to mess up, you can continue
to use 8-space tabs.
Okay: a = 1
Okay: if a == 0:\n a = 1
E111: a = 1
E114: # a = 1
Okay: for item in items:\n pass
E112: for item in items:\npass
E115: for item in items:\n# Hi\n pass
Okay: a = 1\nb = 2
E113: a = 1\n b = 2
E116: a = 1\n # b = 2
At least two spaces before inline comment Open
elif mnem == 'jb': # jnae jc
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Separate inline comments by at least two spaces.
An inline comment is a comment on the same line as a statement.
Inline comments should be separated by at least two spaces from the
statement. They should start with a # and a single space.
Each line of a block comment starts with a # and a single space
(unless it is indented text inside the comment).
Okay: x = x + 1 # Increment x
Okay: x = x + 1 # Increment x
Okay: # Block comment
E261: x = x + 1 # Increment x
E262: x = x + 1 #Increment x
E262: x = x + 1 # Increment x
E265: #Block comment
E266: ### Block comment
Indentation is not a multiple of 4 Open
if dest_false and (dest_false in blocks or (len(list(dest_false.jump_from)) == 1 and not dest_false.node.is_return_node and dest_true not in exclude)):
- Read upRead up
- Exclude checks
Use indent_size (PEP8 says 4) spaces per indentation level.
For really old code that you don't want to mess up, you can continue
to use 8-space tabs.
Okay: a = 1
Okay: if a == 0:\n a = 1
E111: a = 1
E114: # a = 1
Okay: for item in items:\n pass
E112: for item in items:\npass
E115: for item in items:\n# Hi\n pass
Okay: a = 1\nb = 2
E113: a = 1\n b = 2
E116: a = 1\n # b = 2
Line too long (84 > 79 characters) Open
if cond.top in blocks and cond.top not in [loop.start for loop in self.loops]:
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Limit all lines to a maximum of 79 characters.
There are still many devices around that are limited to 80 character
lines; plus, limiting windows to 80 characters makes it possible to
have several windows side-by-side. The default wrapping on such
devices looks ugly. Therefore, please limit all lines to a maximum
of 79 characters. For flowing long blocks of text (docstrings or
comments), limiting the length to 72 characters is recommended.
Reports error E501.
Indentation is not a multiple of 4 Open
elif mnem == 'jg': # jnle
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- Exclude checks
Use indent_size (PEP8 says 4) spaces per indentation level.
For really old code that you don't want to mess up, you can continue
to use 8-space tabs.
Okay: a = 1
Okay: if a == 0:\n a = 1
E111: a = 1
E114: # a = 1
Okay: for item in items:\n pass
E112: for item in items:\npass
E115: for item in items:\n# Hi\n pass
Okay: a = 1\nb = 2
E113: a = 1\n b = 2
E116: a = 1\n # b = 2
Continuation line over-indented for visual indent Open
type(expr.op1) == sign_t and type(expr.op2) == overflow_t and \
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Continuation lines indentation.
Continuation lines should align wrapped elements either vertically
using Python's implicit line joining inside parentheses, brackets
and braces, or using a hanging indent.
When using a hanging indent these considerations should be applied:
- there should be no arguments on the first line, and
- further indentation should be used to clearly distinguish itself
as a continuation line.
Okay: a = (\n)
E123: a = (\n )
Okay: a = (\n 42)
E121: a = (\n 42)
E122: a = (\n42)
E123: a = (\n 42\n )
E124: a = (24,\n 42\n)
E125: if (\n b):\n pass
E126: a = (\n 42)
E127: a = (24,\n 42)
E128: a = (24,\n 42)
E129: if (a or\n b):\n pass
E131: a = (\n 42\n 24)
Indentation is not a multiple of 4 Open
yield expr
- Read upRead up
- Exclude checks
Use indent_size (PEP8 says 4) spaces per indentation level.
For really old code that you don't want to mess up, you can continue
to use 8-space tabs.
Okay: a = 1
Okay: if a == 0:\n a = 1
E111: a = 1
E114: # a = 1
Okay: for item in items:\n pass
E112: for item in items:\npass
E115: for item in items:\n# Hi\n pass
Okay: a = 1\nb = 2
E113: a = 1\n b = 2
E116: a = 1\n # b = 2
Indentation is not a multiple of 4 Open
is_aeq = lambda expr: type(expr) == b_and_t and \
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- Exclude checks
Use indent_size (PEP8 says 4) spaces per indentation level.
For really old code that you don't want to mess up, you can continue
to use 8-space tabs.
Okay: a = 1
Okay: if a == 0:\n a = 1
E111: a = 1
E114: # a = 1
Okay: for item in items:\n pass
E112: for item in items:\npass
E115: for item in items:\n# Hi\n pass
Okay: a = 1\nb = 2
E113: a = 1\n b = 2
E116: a = 1\n # b = 2