Competitive Coding/Bitwise Operations/Largest_power_of_2/Largest_power_2.cpp
#include <iostream>
using namespace std;
int main() {
long N;
cin>>N;
largest_power(N);}
void largest_power(long N)
{
//changing all right side bits to 1.
N = N| (N>>1);
N = N| (N>>2);
N = N| (N>>4);
N = N| (N>>8);
//as now the number is 2 * x-1, where x is required answer, so adding 1 and dividing it by
2.
printf((N+1)>>1;
}