Function check_devices has a Cognitive Complexity of 8 (exceeds 5 allowed). Consider refactoring.

Open

    def check_devices(self):
        devs = os.listdir('/dev/')
        hds = []

        print("Searching hd devices...")

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Avoid deeply nested control flow statements.

Open

                            if len(mountpoint) != 0:
                                print("  Found: " + j[0] + " -> /dev/" + j[1] + " -> " + j[2] + " -> " + uuid_sup + ' -> ' + mountpoint)
                                self.exslin = True
                                tablemount.append([j[0], j[1], j[2], mountpoint])

Avoid deeply nested control flow statements.

Open

                        if os.path.exists("/mnt/RCSPE/files/LINUX/") == False:
                            self.stalin = False
                            self.liclin = False

                            print("  Not found: Linux license")

Avoid deeply nested control flow statements.

Open

                            if svalue == True:
                                self.crylin = True

Avoid deeply nested control flow statements.

Open

                            if ret != 0:
                                uuid_sup = "UUID"
                                uuid = subprocess.check_output("blkid | grep -i '{}' | awk '{{print $2}}'".format(j[1]), shell=True)[6:-2].decode('utf-8')
                                mountpoint = subprocess.check_output("cat /mnt/etc/fstab 2> /dev/null | grep -v '#' | grep -i {} | egrep ' / | /home | /var ' | awk '{{print $2}}'".format(uuid), shell=True)[:-1].decode('utf-8')

Avoid deeply nested control flow statements.

Open

                        if subprocess.check_output("ls -l /mnt2/ | grep '{}' | grep -i '^d' | wc -l".format(line[0]), shell=True).decode('utf-8')[:-1] == '0':
                            break

Consider simplifying this complex logical expression.

Open

            if is_dir == False and is_temp_dir == False:
                print("        " + i['username'] + " status is: not infected") 
                i['status'] = None 
            elif is_temp_file1 == True and is_temp_file2 == True and is_dir == False:
                print("        " + i['username'] + " status is: infected")

Consider simplifying this complex logical expression.

Open

        if osversion.find("10.5") != -1 or osversion.find("10.6") != -1 or osversion.find("10.7") != -1 or osversion.find("10.8") != -1 or osversion.find("10.9") != -1 or osversion.find("10.10") != -1:
            ossupport = True

Consider simplifying this complex logical expression.

Open

            if i[0] == 'linux' and i[3] == '/':
                tablelinux.update({'rootdisk': i[1]})
                tablelinux.update({'rootfs': i[2]})
                tablelinux.update({'rootmount': i[3]})
            elif i[0] == 'linux' and i[3] == ('/home' or '/home/'):

Function check_ossystems has a Cognitive Complexity of 7 (exceeds 5 allowed). Consider refactoring.

Open

    def check_ossystems(self):
        tablemount = self.check_mount()
        tableosx = {}
        tablelinux = {}

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Avoid too many return statements within this function.

Open

        return [False, False]

Avoid too many return statements within this function.

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            return [True, False]

Avoid too many return statements within this function.

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        return True

Avoid too many return statements within this function.

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            return False

Avoid too many return statements within this function.

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        return True

Avoid too many return statements within this function.

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            return False

Avoid too many return statements within this function.

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        return True

Avoid too many return statements within this function.

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        return True

Avoid too many return statements within this function.

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            return False

Avoid too many return statements within this function.

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            return False