Maroc-OS/decompiler

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Indentation is not a multiple of 4
Open

      stmt.container.insert(stmt.index(), continue_t(stmt.ea))
Severity: Minor
Found in src/filters/controlflow.py by pep8

Use indent_size (PEP8 says 4) spaces per indentation level.

For really old code that you don't want to mess up, you can continue
to use 8-space tabs.

Okay: a = 1
Okay: if a == 0:\n    a = 1
E111:   a = 1
E114:   # a = 1

Okay: for item in items:\n    pass
E112: for item in items:\npass
E115: for item in items:\n# Hi\n    pass

Okay: a = 1\nb = 2
E113: a = 1\n    b = 2
E116: a = 1\n    # b = 2

Indentation is not a multiple of 4
Open

      container.add(stmt)
Severity: Minor
Found in src/filters/controlflow.py by pep8

Use indent_size (PEP8 says 4) spaces per indentation level.

For really old code that you don't want to mess up, you can continue
to use 8-space tabs.

Okay: a = 1
Okay: if a == 0:\n    a = 1
E111:   a = 1
E114:   # a = 1

Okay: for item in items:\n    pass
E112: for item in items:\npass
E115: for item in items:\n# Hi\n    pass

Okay: a = 1\nb = 2
E113: a = 1\n    b = 2
E116: a = 1\n    # b = 2

Indentation is not a multiple of 4
Open

      if loop.start in blocks:
Severity: Minor
Found in src/filters/controlflow.py by pep8

Use indent_size (PEP8 says 4) spaces per indentation level.

For really old code that you don't want to mess up, you can continue
to use 8-space tabs.

Okay: a = 1
Okay: if a == 0:\n    a = 1
E111:   a = 1
E114:   # a = 1

Okay: for item in items:\n    pass
E112: for item in items:\npass
E115: for item in items:\n# Hi\n    pass

Okay: a = 1\nb = 2
E113: a = 1\n    b = 2
E116: a = 1\n    # b = 2

Continuation line over-indented for visual indent
Open

        type(expr.op1) == sign_t and type(expr.op2) == overflow_t and \
Severity: Minor
Found in src/filters/simplify_expressions.py by pep8

Continuation lines indentation.

Continuation lines should align wrapped elements either vertically
using Python's implicit line joining inside parentheses, brackets
and braces, or using a hanging indent.

When using a hanging indent these considerations should be applied:
- there should be no arguments on the first line, and
- further indentation should be used to clearly distinguish itself
  as a continuation line.

Okay: a = (\n)
E123: a = (\n    )

Okay: a = (\n    42)
E121: a = (\n   42)
E122: a = (\n42)
E123: a = (\n    42\n    )
E124: a = (24,\n     42\n)
E125: if (\n    b):\n    pass
E126: a = (\n        42)
E127: a = (24,\n      42)
E128: a = (24,\n    42)
E129: if (a or\n    b):\n    pass
E131: a = (\n    42\n 24)

Indentation is not a multiple of 4 (comment)
Open

  # unsigned above-than
Severity: Minor
Found in src/filters/simplify_expressions.py by pep8

Use indent_size (PEP8 says 4) spaces per indentation level.

For really old code that you don't want to mess up, you can continue
to use 8-space tabs.

Okay: a = 1
Okay: if a == 0:\n    a = 1
E111:   a = 1
E114:   # a = 1

Okay: for item in items:\n    pass
E112: for item in items:\npass
E115: for item in items:\n# Hi\n    pass

Okay: a = 1\nb = 2
E113: a = 1\n    b = 2
E116: a = 1\n    # b = 2

Indentation is not a multiple of 4
Open

  elif is_leq(expr):
Severity: Minor
Found in src/filters/simplify_expressions.py by pep8

Use indent_size (PEP8 says 4) spaces per indentation level.

For really old code that you don't want to mess up, you can continue
to use 8-space tabs.

Okay: a = 1
Okay: if a == 0:\n    a = 1
E111:   a = 1
E114:   # a = 1

Okay: for item in items:\n    pass
E112: for item in items:\npass
E115: for item in items:\n# Hi\n    pass

Okay: a = 1\nb = 2
E113: a = 1\n    b = 2
E116: a = 1\n    # b = 2

Indentation is not a multiple of 4
Open

  else:
Severity: Minor
Found in src/filters/simplify_expressions.py by pep8

Use indent_size (PEP8 says 4) spaces per indentation level.

For really old code that you don't want to mess up, you can continue
to use 8-space tabs.

Okay: a = 1
Okay: if a == 0:\n    a = 1
E111:   a = 1
E114:   # a = 1

Okay: for item in items:\n    pass
E112: for item in items:\npass
E115: for item in items:\n# Hi\n    pass

Okay: a = 1\nb = 2
E113: a = 1\n    b = 2
E116: a = 1\n    # b = 2

Indentation is not a multiple of 4 (comment)
Open

  # !(a && b) becomes !a || !b
Severity: Minor
Found in src/filters/simplify_expressions.py by pep8

Use indent_size (PEP8 says 4) spaces per indentation level.

For really old code that you don't want to mess up, you can continue
to use 8-space tabs.

Okay: a = 1
Okay: if a == 0:\n    a = 1
E111:   a = 1
E114:   # a = 1

Okay: for item in items:\n    pass
E112: for item in items:\npass
E115: for item in items:\n# Hi\n    pass

Okay: a = 1\nb = 2
E113: a = 1\n    b = 2
E116: a = 1\n    # b = 2

Indentation is not a multiple of 4
Open

      yield assign_t(self.zf.copy(), eq_t(self.eflags_expr.copy(), value_t(0, 1)))
Severity: Minor
Found in src/ir/intel.py by pep8

Use indent_size (PEP8 says 4) spaces per indentation level.

For really old code that you don't want to mess up, you can continue
to use 8-space tabs.

Okay: a = 1
Okay: if a == 0:\n    a = 1
E111:   a = 1
E114:   # a = 1

Okay: for item in items:\n    pass
E112: for item in items:\npass
E115: for item in items:\n# Hi\n    pass

Okay: a = 1\nb = 2
E113: a = 1\n    b = 2
E116: a = 1\n    # b = 2

Indentation is not a multiple of 4
Open

  def evaluate_flags(self, expr, flags):
Severity: Minor
Found in src/ir/intel.py by pep8

Use indent_size (PEP8 says 4) spaces per indentation level.

For really old code that you don't want to mess up, you can continue
to use 8-space tabs.

Okay: a = 1
Okay: if a == 0:\n    a = 1
E111:   a = 1
E114:   # a = 1

Okay: for item in items:\n    pass
E112: for item in items:\npass
E115: for item in items:\n# Hi\n    pass

Okay: a = 1\nb = 2
E113: a = 1\n    b = 2
E116: a = 1\n    # b = 2

Indentation is not a multiple of 4
Open

      yield assign_t(self.pf.copy(), value_t(value, 1))
Severity: Minor
Found in src/ir/intel.py by pep8

Use indent_size (PEP8 says 4) spaces per indentation level.

For really old code that you don't want to mess up, you can continue
to use 8-space tabs.

Okay: a = 1
Okay: if a == 0:\n    a = 1
E111:   a = 1
E114:   # a = 1

Okay: for item in items:\n    pass
E112: for item in items:\npass
E115: for item in items:\n# Hi\n    pass

Okay: a = 1\nb = 2
E113: a = 1\n    b = 2
E116: a = 1\n    # b = 2

Indentation is not a multiple of 4 (comment)
Open

      #~ assert insn.Op1.type == 1
Severity: Minor
Found in src/ir/intel.py by pep8

Use indent_size (PEP8 says 4) spaces per indentation level.

For really old code that you don't want to mess up, you can continue
to use 8-space tabs.

Okay: a = 1
Okay: if a == 0:\n    a = 1
E111:   a = 1
E114:   # a = 1

Okay: for item in items:\n    pass
E112: for item in items:\npass
E115: for item in items:\n# Hi\n    pass

Okay: a = 1\nb = 2
E113: a = 1\n    b = 2
E116: a = 1\n    # b = 2

Indentation is not a multiple of 4
Open

      yield expr
Severity: Minor
Found in src/ir/intel.py by pep8

Use indent_size (PEP8 says 4) spaces per indentation level.

For really old code that you don't want to mess up, you can continue
to use 8-space tabs.

Okay: a = 1
Okay: if a == 0:\n    a = 1
E111:   a = 1
E114:   # a = 1

Okay: for item in items:\n    pass
E112: for item in items:\npass
E115: for item in items:\n# Hi\n    pass

Okay: a = 1\nb = 2
E113: a = 1\n    b = 2
E116: a = 1\n    # b = 2

Indentation is not a multiple of 4
Open

      expr = assign_t(self.leavereg.copy(), deref_t(self.stackreg.copy(), self.address_size))
Severity: Minor
Found in src/ir/intel.py by pep8

Use indent_size (PEP8 says 4) spaces per indentation level.

For really old code that you don't want to mess up, you can continue
to use 8-space tabs.

Okay: a = 1
Okay: if a == 0:\n    a = 1
E111:   a = 1
E114:   # a = 1

Okay: for item in items:\n    pass
E112: for item in items:\npass
E115: for item in items:\n# Hi\n    pass

Okay: a = 1\nb = 2
E113: a = 1\n    b = 2
E116: a = 1\n    # b = 2

Indentation is not a multiple of 4
Open

      op = self.get_operand_expression(ea, 1)
Severity: Minor
Found in src/ir/intel.py by pep8

Use indent_size (PEP8 says 4) spaces per indentation level.

For really old code that you don't want to mess up, you can continue
to use 8-space tabs.

Okay: a = 1
Okay: if a == 0:\n    a = 1
E111:   a = 1
E114:   # a = 1

Okay: for item in items:\n    pass
E112: for item in items:\npass
E115: for item in items:\n# Hi\n    pass

Okay: a = 1\nb = 2
E113: a = 1\n    b = 2
E116: a = 1\n    # b = 2

Line too long (83 > 79 characters)
Open

      # call is a special case: we analyse the target functions's flow to determine
Severity: Minor
Found in src/ir/intel.py by pep8

Limit all lines to a maximum of 79 characters.

There are still many devices around that are limited to 80 character
lines; plus, limiting windows to 80 characters makes it possible to
have several windows side-by-side.  The default wrapping on such
devices looks ugly.  Therefore, please limit all lines to a maximum
of 79 characters. For flowing long blocks of text (docstrings or
comments), limiting the length to 72 characters is recommended.

Reports error E501.

Indentation is not a multiple of 4 (comment)
Open

      # the likely parameters.
Severity: Minor
Found in src/ir/intel.py by pep8

Use indent_size (PEP8 says 4) spaces per indentation level.

For really old code that you don't want to mess up, you can continue
to use 8-space tabs.

Okay: a = 1
Okay: if a == 0:\n    a = 1
E111:   a = 1
E114:   # a = 1

Okay: for item in items:\n    pass
E112: for item in items:\npass
E115: for item in items:\n# Hi\n    pass

Okay: a = 1\nb = 2
E113: a = 1\n    b = 2
E116: a = 1\n    # b = 2

Indentation is not a multiple of 4
Open

      yield expr
Severity: Minor
Found in src/ir/intel.py by pep8

Use indent_size (PEP8 says 4) spaces per indentation level.

For really old code that you don't want to mess up, you can continue
to use 8-space tabs.

Okay: a = 1
Okay: if a == 0:\n    a = 1
E111:   a = 1
E114:   # a = 1

Okay: for item in items:\n    pass
E112: for item in items:\npass
E115: for item in items:\n# Hi\n    pass

Okay: a = 1\nb = 2
E113: a = 1\n    b = 2
E116: a = 1\n    # b = 2

Indentation is not a multiple of 4
Open

      choices = {'add': add_t, 'sub': sub_t}
Severity: Minor
Found in src/ir/intel.py by pep8

Use indent_size (PEP8 says 4) spaces per indentation level.

For really old code that you don't want to mess up, you can continue
to use 8-space tabs.

Okay: a = 1
Okay: if a == 0:\n    a = 1
E111:   a = 1
E114:   # a = 1

Okay: for item in items:\n    pass
E112: for item in items:\npass
E115: for item in items:\n# Hi\n    pass

Okay: a = 1\nb = 2
E113: a = 1\n    b = 2
E116: a = 1\n    # b = 2

Indentation is not a multiple of 4
Open

      for _expr in self.evaluate_flags(expr, CF | PF | AF | ZF | SF | OF):
Severity: Minor
Found in src/ir/intel.py by pep8

Use indent_size (PEP8 says 4) spaces per indentation level.

For really old code that you don't want to mess up, you can continue
to use 8-space tabs.

Okay: a = 1
Okay: if a == 0:\n    a = 1
E111:   a = 1
E114:   # a = 1

Okay: for item in items:\n    pass
E112: for item in items:\npass
E115: for item in items:\n# Hi\n    pass

Okay: a = 1\nb = 2
E113: a = 1\n    b = 2
E116: a = 1\n    # b = 2
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