Showing 2,968 of 2,968 total issues
Indentation is not a multiple of 4 Open
elif mnem == 'jnb': # jae jnc
- Read upRead up
- Exclude checks
Use indent_size (PEP8 says 4) spaces per indentation level.
For really old code that you don't want to mess up, you can continue
to use 8-space tabs.
Okay: a = 1
Okay: if a == 0:\n a = 1
E111: a = 1
E114: # a = 1
Okay: for item in items:\n pass
E112: for item in items:\npass
E115: for item in items:\n# Hi\n pass
Okay: a = 1\nb = 2
E113: a = 1\n b = 2
E116: a = 1\n # b = 2
Indentation is not a multiple of 4 Open
def visit(function, block, conds, visited, context, priors):
- Read upRead up
- Exclude checks
Use indent_size (PEP8 says 4) spaces per indentation level.
For really old code that you don't want to mess up, you can continue
to use 8-space tabs.
Okay: a = 1
Okay: if a == 0:\n a = 1
E111: a = 1
E114: # a = 1
Okay: for item in items:\n pass
E112: for item in items:\npass
E115: for item in items:\n# Hi\n pass
Okay: a = 1\nb = 2
E113: a = 1\n b = 2
E116: a = 1\n # b = 2
Indentation is not a multiple of 4 Open
def expand_branches(self, blocks=None):
- Read upRead up
- Exclude checks
Use indent_size (PEP8 says 4) spaces per indentation level.
For really old code that you don't want to mess up, you can continue
to use 8-space tabs.
Okay: a = 1
Okay: if a == 0:\n a = 1
E111: a = 1
E114: # a = 1
Okay: for item in items:\n pass
E112: for item in items:\npass
E115: for item in items:\n# Hi\n pass
Okay: a = 1\nb = 2
E113: a = 1\n b = 2
E116: a = 1\n # b = 2
Indentation is not a multiple of 4 Open
elif mnem == 'ja': # jnbe
- Read upRead up
- Exclude checks
Use indent_size (PEP8 says 4) spaces per indentation level.
For really old code that you don't want to mess up, you can continue
to use 8-space tabs.
Okay: a = 1
Okay: if a == 0:\n a = 1
E111: a = 1
E114: # a = 1
Okay: for item in items:\n pass
E112: for item in items:\npass
E115: for item in items:\n# Hi\n pass
Okay: a = 1\nb = 2
E113: a = 1\n b = 2
E116: a = 1\n # b = 2
Indentation is not a multiple of 4 Open
goto_true = goto_t(stmt.ea, stmt.true.copy())
- Read upRead up
- Exclude checks
Use indent_size (PEP8 says 4) spaces per indentation level.
For really old code that you don't want to mess up, you can continue
to use 8-space tabs.
Okay: a = 1
Okay: if a == 0:\n a = 1
E111: a = 1
E114: # a = 1
Okay: for item in items:\n pass
E112: for item in items:\npass
E115: for item in items:\n# Hi\n pass
Okay: a = 1\nb = 2
E113: a = 1\n b = 2
E116: a = 1\n # b = 2
Indentation is not a multiple of 4 Open
elif mnem == 'jge': # jnl
- Read upRead up
- Exclude checks
Use indent_size (PEP8 says 4) spaces per indentation level.
For really old code that you don't want to mess up, you can continue
to use 8-space tabs.
Okay: a = 1
Okay: if a == 0:\n a = 1
E111: a = 1
E114: # a = 1
Okay: for item in items:\n pass
E112: for item in items:\npass
E115: for item in items:\n# Hi\n pass
Okay: a = 1\nb = 2
E113: a = 1\n b = 2
E116: a = 1\n # b = 2
Indentation is not a multiple of 4 Open
_if = if_t(stmt.ea, condition, container_t(stmt.container.block, [goto_true]))
- Read upRead up
- Exclude checks
Use indent_size (PEP8 says 4) spaces per indentation level.
For really old code that you don't want to mess up, you can continue
to use 8-space tabs.
Okay: a = 1
Okay: if a == 0:\n a = 1
E111: a = 1
E114: # a = 1
Okay: for item in items:\n pass
E112: for item in items:\npass
E115: for item in items:\n# Hi\n pass
Okay: a = 1\nb = 2
E113: a = 1\n b = 2
E116: a = 1\n # b = 2
Indentation is not a multiple of 4 Open
else:
- Read upRead up
- Exclude checks
Use indent_size (PEP8 says 4) spaces per indentation level.
For really old code that you don't want to mess up, you can continue
to use 8-space tabs.
Okay: a = 1
Okay: if a == 0:\n a = 1
E111: a = 1
E114: # a = 1
Okay: for item in items:\n pass
E112: for item in items:\npass
E115: for item in items:\n# Hi\n pass
Okay: a = 1\nb = 2
E113: a = 1\n b = 2
E116: a = 1\n # b = 2
Indentation is not a multiple of 4 Open
stmt.container.insert(stmt.index(), _if)
- Read upRead up
- Exclude checks
Use indent_size (PEP8 says 4) spaces per indentation level.
For really old code that you don't want to mess up, you can continue
to use 8-space tabs.
Okay: a = 1
Okay: if a == 0:\n a = 1
E111: a = 1
E114: # a = 1
Okay: for item in items:\n pass
E112: for item in items:\npass
E115: for item in items:\n# Hi\n pass
Okay: a = 1\nb = 2
E113: a = 1\n b = 2
E116: a = 1\n # b = 2
Indentation is not a multiple of 4 Open
def get_register_size(self, which):
- Read upRead up
- Exclude checks
Use indent_size (PEP8 says 4) spaces per indentation level.
For really old code that you don't want to mess up, you can continue
to use 8-space tabs.
Okay: a = 1
Okay: if a == 0:\n a = 1
E111: a = 1
E114: # a = 1
Okay: for item in items:\n pass
E112: for item in items:\npass
E115: for item in items:\n# Hi\n pass
Okay: a = 1\nb = 2
E113: a = 1\n b = 2
E116: a = 1\n # b = 2
Indentation is not a multiple of 4 Open
stmt.remove()
- Read upRead up
- Exclude checks
Use indent_size (PEP8 says 4) spaces per indentation level.
For really old code that you don't want to mess up, you can continue
to use 8-space tabs.
Okay: a = 1
Okay: if a == 0:\n a = 1
E111: a = 1
E114: # a = 1
Okay: for item in items:\n pass
E112: for item in items:\npass
E115: for item in items:\n# Hi\n pass
Okay: a = 1\nb = 2
E113: a = 1\n b = 2
E116: a = 1\n # b = 2
Indentation is not a multiple of 4 Open
def attach_breaks(self):
- Read upRead up
- Exclude checks
Use indent_size (PEP8 says 4) spaces per indentation level.
For really old code that you don't want to mess up, you can continue
to use 8-space tabs.
Okay: a = 1
Okay: if a == 0:\n a = 1
E111: a = 1
E114: # a = 1
Okay: for item in items:\n pass
E112: for item in items:\npass
E115: for item in items:\n# Hi\n pass
Okay: a = 1\nb = 2
E113: a = 1\n b = 2
E116: a = 1\n # b = 2
Indentation is not a multiple of 4 Open
if stmt.true.value == block.ea:
- Read upRead up
- Exclude checks
Use indent_size (PEP8 says 4) spaces per indentation level.
For really old code that you don't want to mess up, you can continue
to use 8-space tabs.
Okay: a = 1
Okay: if a == 0:\n a = 1
E111: a = 1
E114: # a = 1
Okay: for item in items:\n pass
E112: for item in items:\npass
E115: for item in items:\n# Hi\n pass
Okay: a = 1\nb = 2
E113: a = 1\n b = 2
E116: a = 1\n # b = 2
Indentation is not a multiple of 4 Open
if len(to) == 1 and to[0] is not exit and to[0] in self.exits:
- Read upRead up
- Exclude checks
Use indent_size (PEP8 says 4) spaces per indentation level.
For really old code that you don't want to mess up, you can continue
to use 8-space tabs.
Okay: a = 1
Okay: if a == 0:\n a = 1
E111: a = 1
E114: # a = 1
Okay: for item in items:\n pass
E112: for item in items:\npass
E115: for item in items:\n# Hi\n pass
Okay: a = 1\nb = 2
E113: a = 1\n b = 2
E116: a = 1\n # b = 2
Line too long (96 > 79 characters) Open
branches = (self.function.blocks[stmt.true.value], self.function.blocks[stmt.false.value])
- Read upRead up
- Exclude checks
Limit all lines to a maximum of 79 characters.
There are still many devices around that are limited to 80 character
lines; plus, limiting windows to 80 characters makes it possible to
have several windows side-by-side. The default wrapping on such
devices looks ugly. Therefore, please limit all lines to a maximum
of 79 characters. For flowing long blocks of text (docstrings or
comments), limiting the length to 72 characters is recommended.
Reports error E501.
Indentation is not a multiple of 4 Open
left = list(reversed(prior[1:i]))
- Read upRead up
- Exclude checks
Use indent_size (PEP8 says 4) spaces per indentation level.
For really old code that you don't want to mess up, you can continue
to use 8-space tabs.
Okay: a = 1
Okay: if a == 0:\n a = 1
E111: a = 1
E114: # a = 1
Okay: for item in items:\n pass
E112: for item in items:\npass
E115: for item in items:\n# Hi\n pass
Okay: a = 1\nb = 2
E113: a = 1\n b = 2
E116: a = 1\n # b = 2
Indentation is not a multiple of 4 Open
def wrap_loop(self, ea, klass, block, condition):
- Read upRead up
- Exclude checks
Use indent_size (PEP8 says 4) spaces per indentation level.
For really old code that you don't want to mess up, you can continue
to use 8-space tabs.
Okay: a = 1
Okay: if a == 0:\n a = 1
E111: a = 1
E114: # a = 1
Okay: for item in items:\n pass
E112: for item in items:\npass
E115: for item in items:\n# Hi\n pass
Okay: a = 1\nb = 2
E113: a = 1\n b = 2
E116: a = 1\n # b = 2
Line too long (95 > 79 characters) Open
if len(set(branches).intersection(self.loop.exits)) == 1 and self.loop.start in branches:
- Read upRead up
- Exclude checks
Limit all lines to a maximum of 79 characters.
There are still many devices around that are limited to 80 character
lines; plus, limiting windows to 80 characters makes it possible to
have several windows side-by-side. The default wrapping on such
devices looks ugly. Therefore, please limit all lines to a maximum
of 79 characters. For flowing long blocks of text (docstrings or
comments), limiting the length to 72 characters is recommended.
Reports error E501.
Line too long (80 > 79 characters) Open
_while = self.wrap_loop(None, while_t, self.loop.blocks[0], value_t(1, 1))
- Read upRead up
- Exclude checks
Limit all lines to a maximum of 79 characters.
There are still many devices around that are limited to 80 character
lines; plus, limiting windows to 80 characters makes it possible to
have several windows side-by-side. The default wrapping on such
devices looks ugly. Therefore, please limit all lines to a maximum
of 79 characters. For flowing long blocks of text (docstrings or
comments), limiting the length to 72 characters is recommended.
Reports error E501.
Indentation is not a multiple of 4 Open
def prioritize_non_conditional_block(self, left, right):
- Read upRead up
- Exclude checks
Use indent_size (PEP8 says 4) spaces per indentation level.
For really old code that you don't want to mess up, you can continue
to use 8-space tabs.
Okay: a = 1
Okay: if a == 0:\n a = 1
E111: a = 1
E114: # a = 1
Okay: for item in items:\n pass
E112: for item in items:\npass
E115: for item in items:\n# Hi\n pass
Okay: a = 1\nb = 2
E113: a = 1\n b = 2
E116: a = 1\n # b = 2